x^2+6.5x-48=0

Solution for x^2+6.5x-48=0 equation:

x^2+6.5x-48=0

a = 1; b = 6.5; c = -48;
Δ = b2-4ac
Δ = 6.52-4·1·(-48)
Δ = 234.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.5)-\sqrt{234.25}}{2*1}=\frac{-6.5-\sqrt{234.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.5)+\sqrt{234.25}}{2*1}=\frac{-6.5+\sqrt{234.25}}{2}
$